Монгол Бодлогын Сан

Заавар: $\left(6\dfrac59\overset{\color{red}{\mathrm{I}}}{-}3\dfrac14\right)\overset{\color{red}{\mathrm{II}}}{\cdot}2\dfrac{2}{17}$ байна.

Бодолт: I. $6\dfrac59-3\dfrac14=(6-3)+\Big(\dfrac59^{(4}-\dfrac14^{(9}\Big)=3+\dfrac{20-9}{36}=3\dfrac{11}{36}$.

II. $3\dfrac{11}{36}\cdot 2\dfrac{2}{17}=\dfrac{3\cdot36+11}{36}\cdot \dfrac{2\cdot 17+2}{17}=\dfrac{119}{\color{red}{36}}\cdot\dfrac{\color{red}{36}}{17}=\dfrac{119}{17}=7$.