Монгол Бодлогын Сан

$\dfrac{x^{-\frac12}\cdot\sqrt{x-1}\Big(1-\dfrac1{x^2}\Big)^{-0,5}}{2(x+1)^{-\frac12}}-\sqrt{3-\dfrac1{x^2}\cdot\sqrt{1-\dfrac1{x^2}}}:\dfrac{\left[\dfrac1{9^{-0,5}}-\dfrac{x^{-3}}{(x^2-1)^{-\frac12}}\right]^{0,5}}{x^{\frac12}}+\dfrac{\sqrt x}{2}$ илэрхийллийг хялбарчил.