Монгол Бодлогын Сан

Заавар: $$\log_{a}b<\log_{a}c\Leftrightarrow (a-1)(b-c)<0$$

Бодолт: $$\left\{\begin{array}{l}\log_{x+\frac{1}{12}}6>\log_{x+\frac{1}{12}}5\\ \log_{x+\frac{1}{14}}6>\log_{x+\frac{1}{14}}7\end{array}\right.\Leftrightarrow\left\{\begin{array}{l}(x+\frac{1}{12}-1)(6-5)>0\\ (x+\frac{1}{14}-1)(6-7)>0\end{array}\right.$$ $$\Leftrightarrow\left\{\begin{array}{l}x-\frac{11}{12}>0\\ x-\frac{13}{14}<0\end{array}\right.\Leftrightarrow\dfrac{11}{12}< x<\dfrac{13}{14}$$