Монгол Бодлогын Сан

Заавар: $\Big(\dfrac{a}{b}\Big)^n=\dfrac{a^n}{b^n}$, $a^{\frac mn}=\sqrt[n]{a^m}$, $a^{-n}=\dfrac{1}{a^n}$ болохыг ашигла.

Бодолт: $$\left(2\dfrac{1}{4}\right)^{-\frac32}=\left(\dfrac{9}{4}\right)^{-\frac32}=\left(\dfrac{3}{2}\right)^{-3}=\left(\dfrac{2}{3}\right)^{3}=\dfrac{8}{27},$$ $$\left(3\dfrac{3}{8}\right)^{-\frac13}=\left(\dfrac{27}{8}\right)^{-\frac13}=\left(\dfrac{3}{2}\right)^{-1}=\dfrac{2}{3}$$ тул $$\left(2\dfrac{1}{4}\right)^{-\frac32}\cdot\left(3\dfrac{3}{8}\right)^{-\frac13}=\left(\dfrac{2}{3}\right)^{3}\cdot\dfrac{2}{3}=\dfrac{16}{81}$$