Монгол Бодлогын Сан

Заавар: $\big(\frac{2}{5}\big)^{-2}=\big(\frac{5}{2}\big)^{2}$.

Бодолт: \begin{align*} \text{Илэрх.}&=\Big(\frac{2}{5}\Big)^{-2}\cdot\Big(\frac{3}{5}\Big)^3\cdot\Big(\frac{2}{3}\Big)^2\\ &=\Big(\frac{5}{2}\Big)^{2}\cdot\Big(\frac{3}{5}\Big)^3\cdot\Big(\frac{2}{3}\Big)^2 & &\color{WildStrawberry}{\leftarrow\Big(\dfrac{a}{b}\Big)^{-n}=\Big(\dfrac{b}{a}\Big)^{n}}\\ &=\dfrac{5^2\cdot 3^3\cdot 2^2}{2^2\cdot 5^3\cdot 3^2}\\ &=5^{2-3}\cdot3^{3-2}\cdot 2^{2-2}\\ &=5^{-1}\cdot 3^1\cdot 2^0=\dfrac{3}{5} \end{align*}